Hola, necesito ayuda con estos puntos de un taller de Geometría ^^.
1. Una región cuadrada se encierra con una cuerda de 20 m de longitud. ¿Cuál es el área de la región?

2. El área de un cuadrado es 144 m2 Calcular el perímetro.

3. Las caras de un cubo son cuadrados de 6 m de lado. Calcula el área de las caras y el área total del cubo.

4. Se desea pintar una pared de 8 metros de largo y 3 metros de altura. Si el costo de la pintura por cada metro cuadrado es $ 4.850. ¿Cuánto se debe invertir en la pintura de la pared?

5. El área de un rectángulo mide 96 m2. Si la base mide 16 metros. ¿Cuánto mide la altura?

6. Hallar el área de un paralelogramo que tiene 10 cm de base y 4 cm de altura.

And

Step-by-step explanation:me no understand spanish

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!