Find the value of y so that y + 3, 4y + 1, 8y - 3 is an arithmetic progression.
A. 2
B. 3
C. 4
D. 5
E. 6

A

Step-by-step explanation:

The common difference d in an arithmetic sequence is

a₂ - a₁ = a₃ - a₂ , substitute values

4y + 1 - (y + 3) = 8y - 3 - (4y + 1) ← distribute both sides and simplify

4y + 1 - y - 3 = 8y - 3 - 4y - 1

3y - 2 = 4y - 4 ( subtract 3y from both sides )

- 2 = y - 4 ( add 4 to both sides )

2 = y → A

can someone answer this question plz

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