Mathematics, 23.11.2020 14:00 anjumuddin9

An object is launched straight up into the air at an initial velocity of 64 feet per second. It is launched from a height of 6 feet off the ground. Its height H, is
feet, at t seconds is given by the equation H = -166 + 64t + 6. Find all times t
that the object is at a height of 54 feet off the ground. If there are two
solutions, separate them with a comma and no spaces.

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