Which of these four sets of side lengths will form a right triangle? Set 1
StartRoot 2 EndRoot cm, 9 cm, StartRoot 7 EndRoot cm

Set 2
2 in., StartRoot 5 EndRoot in., 9 in.

Set 3
StartRoot 6 EndRoot mm, 2 mm, 10 mm

Set 4
StartRoot 2 EndRoot ft, StartRoot 7 EndRoot ft, 3 ft

Set 1
Set 2
Set 3
Set 4

4

step-by-step explanation:

im pretty sure it's 4 beacsue 8/2 equals 4

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.