Given that for an arithmetic sequence, the first term is q and the second term is qz. (a) Find the common difference d the general term Tn and the sum of the first n terms. Answer must

be in terms of q and z.
(b) Hence, find the sum of the first 10 terms in terms of q and z.

Given that the first term and the second term of an arithmetic sequence is q and qz respectively, therefore:

a. Common difference (d) =

Sum of the first n terms is:

b.

Recall:

Given:

a. Common difference (d) =

Sum of n terms:

b. Sum of the first 10 terms:

In summary, given that the first term and the second term of an arithmetic sequence is q and qz respectively, therefore:

a. Common difference (d) =

Sum of the first n terms is:

b.

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Step-by-step explanation:

Given

Solving (a1): The common difference (d)

d is calculated as

This gives:

Factorize:

Solving (a2): Sum of n terms

This is calculated using:

Substitute values for T1 and d

Factorize:

Solving (b): Sum of first 10.

In this case, n = 10

So:

becomes

i could probably can you me with a question of mine?

step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2