The length of a rectangle is 5 more than twice the width. if the perimeter of the rectangle is 76 meters, find the dimensions of the rectangle and choose the equation that represents the perimeter: 1. 76=2w+5
2. 76=2w+2(2w+5)
3. 76=w+2w+5
4. 76=2w+(2w+5)

Dimensions: 11 meters by 27 meters

2.

Step-by-step explanation:

Finding Dimensions:

The perimeter of a rectangle can be written as where is the length and is the width. It is given that the length is 5 more than twice the length of width and the perimeter of the rectangle is 76 meters.

With this information we can write:

Length =

(perimeter of the rectangle)

Length =

Length =

∴ The dimensions of the rectangle is 11 meters by 27 meters.

Perimeter

Since the length can be written as , the equation that represents the perimeter of the rectangle is

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x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18