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Mathematics, 22.11.2020 02:30 organdonor626
A portion of the quadratic formula proof is shown. fill in the missing reason.
ax^2+bx+c=0 ββ Given
ax^2+bx=-c ββsubtract c from both sides of the equation
x^2+b/a x=-c/a ββ divide both sides of the equation by a
x^2+ b/a x+(b/2a)^2=-c/a+(b/2a)^2 ββ complete the square and add (b/2a)^2 to both sides.
x^2+ b/a x+(b/2a)^2=-c/a+b^2/4a^2 ββ square (b/2a) on the right side of the equation.
x^2+ b/a x+(b/2a)^2=-4ac/4a+b^2/4a^2ββ find a common denominator on the right side of the equation.
x^2+ b/a x+(b/2a)^2=b^2-4ac/4a^2 ββ ?
A-multiply the fractions together on the right side of the equation
B- subtract 4ac on the right side of the equation
C- add 4ac to both sides of the equation
D- add the fractions together on the right side of the equation
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A portion of the quadratic formula proof is shown. fill in the missing reason.
ax^2+bx+c=0 ββ Given...
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