Two ships are sailing parallel to each other. The path of one ship is represented on a coordinate plane as the line y = –13x + 4. The second ship’s path passes through the point (3, 5). Select another point that the path of the second ship passes through.

(0,44)

Step-by-step explanation:

To answer this question, I would start by finding the equation of the second line. You can do that by plugging it into the formula y-y1=m(x-x1). You can take the slope from the first equation, which would be m=-13. So, y-5=-13(x-3). You can simplify that to get y=-13+44. Finally, to get a point, you can plug in almost any value for x and use the value of y to create a point. For example, if you choose x=0, you can get y=44 and the point (0,44)

f(x)=4

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)