Drag and drop the steps to show the process for finding the inverse of the function below. h(x)=x−43

Answer

h^-1(x)= x+43

Explanation

h(x)=x-43

Use substitution

y=x-43

Interchange the variables

x=y-43

Swap the sides

y-43=x

Move the constant to the right

y=x+43

Use substitution

h^-1(x)=x+43

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v