Factor completely > 16x^2 +48xy + 36y^2

4 (3 y + 2 x)^2

Step-by-step explanation:

Factor the following:

36 y^2 + 48 x y + 16 x^2

Hint: | Factor out the greatest common divisor of the coefficients of 36 y^2 + 48 x y + 16 x^2.

Factor 4 out of 36 y^2 + 48 x y + 16 x^2:

4 (9 y^2 + 12 x y + 4 x^2)

Hint: | Factor by grouping.

The coefficient of x^2 is 4 and the coefficient of y^2 is 9. The product of 4 and 9 is 36. The factors of 36 which sum to 12 are 6 and 6. So 9 y^2 + 12 x y + 4 x^2 = 4 x^2 + 6 x y + 6 x y + 9 y^2 = 2 x (3 y + 2 x) + 3 y (3 y + 2 x):

4 2 x (3 y + 2 x) + 3 y (3 y + 2 x)

Hint: | Factor common terms from 2 x (3 y + 2 x) + 3 y (3 y + 2 x).

Factor 3 y + 2 x from 2 x (3 y + 2 x) + 3 y (3 y + 2 x):

4 (3 y + 2 x) (3 y + 2 x)

Hint: | Combine products of like terms.

(3 y + 2 x) (3 y + 2 x) = (3 y + 2 x)^2:

4 (3 y + 2 x)^2

step-by-step explanation:

the true ones are a b and d