If ∆JKL is an equilateral triangle, JK = 13x + 5, KL = 17x – 19, and JL = 8x + 35, what is the value of x?

x = 6

Step-by-step explanation:

Given that Δ JKL  is equilateral then the 3 sides are congruent.

Equate any 2 sides and solve for x, that is

13x + 5 = 8x + 35 ( subtract 8x from both sides )

5x + 5 = 35 ( subtract 5 from both sides )

5x = 30 ( divide both sides by 5 )

x = 6

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

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