Mathematics, 20.11.2020 18:20 donnafranks2003
I have so many on here pleasehelp me it sin algebra1
1) through: (-2, -2), parallel to y = 2x - 1
2) through: (-4, -4), parallel to y = 7 4 x - 1
3) through: (5, -1), parallel to y = -6 5 x - 4
4) through: (-4, -4), parallel to y = 3 2 x + 4
5) through: (1, -1), parallel to y = 1 2 x + 1
6) through: (-1, -2), perp. to y = -3 2 x + 4
7) through: (3, 4), perp. to y = -3 2 x - 4
8) through: (4, 4), perp. to y = -4 9 x - 2
9) through: (-2, 3), perp. to y = -2x + 1
10) through: (2, -3), perp. to y = 2 7 x - 3
Answers: 3
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Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .
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I have so many on here pleasehelp me it sin algebra1
1) through: (-2, -2), parallel to y = 2x - 1...
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