Plz help ASAP. What is an equation of the line that passes through the point (1,6) and is perpendicular to the line x+3y=27

   y = 3x + 3

Step-by-step explanation:

x + 3y = 27

     3y = -x + 27

      y =

      y =

m₁ = -1/3

the slope of the line perpendicular to x + 3y = 27 is m₂ = -1/m₁

    m₂ = = 3 ,  Point (1 , 6)

y - y1 = m (x -x1)

y -6 = 3(x - 1)

y - 6= 3x - 3

    y = 3x - 3 +6

   y = 3x + 3

28

step-by-step explanation:

8+8+6+6

me

step-by-step explanation: