Paul draws △ABC and the medians from vertices A and B. He finds that the medians intersect at a point and he labels this point X. Paul claims that point X lies outside △ABC. Do you think this is possible? Complete the explanation.

The answer is "Through which we can infer that perhaps the ABC triangles is obstinate shaped".

Step-by-step explanation:

Paul draws that ABC as well as the Median triangle from and A and B nodes. If the median passes after a certain point, and his marks the point X. Paul now says point X (i.e., a triangle's center) is outside the ABC triangle.  

They may also conclude that perhaps the ABC triangle does have an obtuse angle because the centroid is in the ring in case of even a severe triangle, that centroid is already on the right triangle in case of the triangle and cases of an obtuse-angled rectangle, the angular velocity is an outside ring.

1e+27

step-by-step explanation:

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation: