A child fills a bucket with sand so that the bucket and sand together weigh 10 lbs, lifts it 2 feet up and then walks along the beach, holding the bucket at a constant height of 2 ft above the ground. How much work is done on the bucket after the child has walked 100 ft?

Total weight, w = 10 lbs.

Height of the bucket, h = 2 feet.

Distance walked, d = 100 ft.

Now, work done in moving the bucket at a height of 2 feet.

W = mgh

W = 2× 32.17×100

W = 6434  lbs ft²/s²

Work done in moving bucket in horizontal direction is zero because it is perpendicular to the force.

Therefore, work done is 6434  lbs ft²/s² .

Hence, this is the required solution.

529 and 531

step-by-step explanation:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: