Aline has a slope of -4/5 . which ordered pairs could be points on a line that is perpendicular to this line? check all that apply.
(–2, 0) and (2, 5)
(–4, 5) and (4, –5)
(–3, 4) and (2, 0)
(1, –1) and (6, –5)
(2, –1) and (10, 9)

Step-by-step explanation:

Given that a  line has a slope of

For any line perpendicular to this line,

the slope of the line =

Let us check whether the given options satisfy this

a) (-2,0) and (2,5)... slope =

Yes true

b) (–4, 5) and (4, –5)... slope =

No not true.

c) (–3, 4) and (2, 0)

Slope =

No not true.

d) (1, –1) and (6, –5)

Slope =

No, not true.

e) (2, –1) and (10, 9)

Slope = 5/4

True.

e) (2, –1) and (10, 9)

the answer is c: divide the arc's degree measure by 360°, then multiply by the circumference of the circle.

well if you have a decimal you have to line them up and make sure the you have everything   straight and then add or subtract some thing with   division and   multiplying so just like them up