MNO and MPO are isosceles triangles. Find angle t

t = 20°

Step-by-step explanation:

Recall that the base angles of an isosceles ∆ are equal to each other.

This means that:

<NMO and <NOM of ∆MNO are congruent to each other.

Thus,

m<NMO = ½(180 - m<N) = ½(180 - 70)

m<NMO = ½(110)

m<NMO = 55°

Also, <PMO and <POM are congruent to each other. Thus:

m<PMO = ½(180 - m<P) = ½(180 - 110)

m<PMO = ½(70)

m<PMO = 35°

Therefore,

m<NMO = t + m<PMO (angle addition postulate)

55° = t + 35° (substitution)

Subtract 35 from each side

55° - 35° = t

20° = t

t = 20°

step-by-step explanation: