The perimeter of a rectangular parking lot is 292 m. If the length of the parking lot is 81 m, what is its width?

the answer would be 211

Step-by-step explanation:

you simply add the length and width together to find perimeter. since you have the total perimeter and the length you would instead subtract the two.

292-81= 211

68m

Step-by-step explanation:

The perimeter  of a rectangle with length  and width  is given by the following.

P=21+2w

We need to find w when P=292 m  and l+78m .

Using these values in the equation above, we'll solve for w.

P=21+2w

292=2(78)+2w

292=156+2w

136=2w

68=w

Subtracting 156  from both sides

Dividing both sides by  2

So the width of the parking lot is 68m

d (5 x (-20)) * (100 x (0.7))

step-by-step explanation:

5÷1/100 * -.7 *-20

copy dot flip

5*100 * -.7 *-20

rearrange

5*-20   * 100 *-.7

-100   *-70

7000