Sharon kicks a ball from the ground into the air with an upward velocity of 64 feet per second. the function h = -16t2 + 64t models the height h, in feet, of the ball at time t, in seconds. when will the ball reach the ground again?

At t = 4 seconds the ball reach the ground again

Step-by-step explanation:

The equation is given by h =-16t²+64t

We need to find when will the ball reach the ground again

When the ball reaches the ground again we have h = 0

That is

                  h =-16t²+64t = 0

                        t ( -16t+64 ) = 0

                   t = 0  or -16t + 64 = 0

                    t = 0  or t = 4

We are asked to find the second time, that is t = 4 seconds.

At t = 4 seconds the ball reach the ground again

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's