PLEASE HURRY!! In the time that it takes Car 1 to travel 93 km, Car 2 travels 111 km. If the average speed of Car 2 is 12 km/hour faster than the speed of Car 1, then what is the speed of Car 2? Write and solve a proportion

Car 1=64 km/h

Car 2=74 km/h

Explanation:

The formula for speed is

s=dt

For the first car, we know d

and plugging it into the formula gives us

s1=93t

We know the second car is

12 km/h

faster and the distance is

111 km

, so the formula in terms of the first car's speed would be

s1+12=111

t=s2

Now we can solve for

s1

in the second equation

s1=111t−12

Now we can set the two

s1

equal to each other and solve for

t93t=111t−1293=111−12t=18t=32hours

Now we can plug

t

into the first car equation to solve for the speed of it

s

1

=93 km32h=62 km/h

We know the second car is

12 km/h

faster, so

62 km/h+12 km/h=74 km/h

Step-by-step explanation:

y=mx+b

step-by-step explanation:

m is slope, b is y-intercept

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.