70%70, percent of a certain species of tomato live after transplanting from pot to garden. Najib transplants 333 of these tomato plants. Assume that the plants live independently of each other. Let X =X=X, equals the number of tomato plants that live. What is the probability that exactly 222 of the 333 tomato plants live?
You may round your answer to the nearest hundredth.

The probability that exactly 2 of the 3 tomato plants live is 0.44

The given parameters are:

--- number of transplants

-- the number that lives

--- the probability that a transplant lives

So, the probability that exactly 2 live is calculated using the following binomial probability formula

This gives

Evaluate each factor

Multiply

Hence, the required probability is 0.44

Read more about probabilities at:

link

Complete question :

70% of a certain species of tomato live after transplanting from pot to garden. Najib transplants 3 of these tomato plants. Assume that the plants live independently of each other. Let X = the number of tomato plants that live.

What is the probability that exactly 2 of the 3 tomato plants live?

You may round your answer to the nearest hundredth.

0.44

Step-by-step explanation:

Given that :

P(live after transplanting) = 0.7

Assume plants live independently of each other :

Number of tomatoes transplanted = 3

Number of potatoes that live = x

Probability that exactly 2 of the 3 tomatoes live?

Using binomial probability ;

p = 0.7

1 - p = 1 - 0. 7 = 0.3

P(x = x) = nCx * p^x * (1 - p)^(n-x)

P(x = 2) = 3C2 * 0.7^2 * 0.3^(3-2)

P(x = 2) = 3C2 * 0.7^2 * 0.3^1

P(x = 2) = 3 * 0.49 * 0.3

P(x = 2) = 0.441

= 0.44 ( nearest hundredth)