Point P on the coordinate grid below shows the location of a stage light. A second stage light is 10 units above P. The length of each square on the grid is 2 units. What are the coordinates of the location of the second stage light? A four-quadrant coordinate grid from negative 16 to positive 16 in increments of 2 is drawn. Point P is plotted on the ordered pair 2, negative 6.

(2, −16)
(12, 4)
(2, 4)
(12, −16)

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).

the answer is 11.2 (i know i’m late)

step-by-step explanation: