Find the height of a sharp-crested free-flow rectangular weir to pass a discharge of 0.4 m/s with an upstream depth of 1.0 m. The width of the weir is 2.0 m and is equal to the width of the channel. Answer choices:
5x-9
6x+20
6x^2-23x+20
6x^2-14x-9

2

step-by-step explanation:

a

step-by-step explanation:

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west