Mathematics, 18.11.2020 19:50 tony7135

Factor 9x^6 - 16y^6 completely. First factor each term.
9x^6 = ()^2
16y^6 = ()^2
Then use a^2-b^2 = (a-b)(a+b). Show your work.
9x^6-16y^6=

Answers: 1

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You know the right answer?

Factor 9x^6 - 16y^6 completely. First factor each term.
9x^6 = (__)^2
16y^6 = (__)^2

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More questions: Mathematics Another questions

Factor 9x^6 - 16y^6 completely. First factor each term. 9x^6 = (__)^2 16y^6 = (__)^2 Then use a^2-b^2 = (a-b)(a+b). Show your work. 9x^6-16y^6=

Answers

Another question on Mathematics

Factor 9x^6 - 16y^6 completely. First factor each term.
9x^6 = ()^2
16y^6 = ()^2
Then use a^2-b^2 = (a-b)(a+b). Show your work.
9x^6-16y^6=