The age of the older of two boys is twice that of the younger; 5 years ago it was three times that of the younger. Find the age of each. pls include steps will mark brainiest

The older boy is now 20, the younger boy is now 10.

Step-by-step explanation: Explanation:

Let the age of the older boy now be y

let the age of the younger boy now be x

y = 2x

y-5 = 3(x-5)

simplifying

y = 3x - 10

substituting for y in equation 1

2x = 3x-10

simplifying

x = 10

substituting into 1

y = 20

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead