An urn contains 17 white balls and 18 red balls. A sample of four balls is selected at random from the urn. What is the probability that the sample contains two white balls and two red ones? a. 0.0286
b. 0.2286
c. 0.3974
d. 0.0944
e. 0.0442
f. None of the above.

c. 0.3974

Step-by-step explanation:

Given;

number of white balls, W = 17

number of red balls, R = 18

Total number of balls, T = 35

The number of ways the event will occur is given by

= P(2 whites) and P(2 reds)

= P(2whites) x P(2 reds)

= 17C2 x 18C2

= 136 x 153

= 20,808

The total number of possible outcome

= 35C4

= 52,360

The probability = 20,808 / 52,360

                          = 0.3974

The correct option is "C"

the fist one is not equalvalent but i think th second one isand the third isnt definetly or the last one is i think. hope this !

step-by-step explanation:

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1