Triangle ABC is dilated using the dilation rule D0.5(x, y) to form triangle A'B'C'. Point A is located at (10, 7.5), point B is located at (–5, 2), and point C is located at (0.5, –7).

The coordinates of A' are .

The coordinates of B' are .

The coordinates of C' are .

Step-by-step explanation:

The statement is incomplete, we present the complete statement below: Triangle ABC is dilated using the dilation rule to form triangle A’B’C’. Point A is located at , point B is located at , and point C is located at . What are the coordinates of A’? What are the coordinates of B’? What are the coordinates of C’?

We proceed to calcultate the coordinates of the triangle A'B'C' hereafter:

What are the coordinates of A'?

(1)

The coordinates of A' are .

What are the coordinates of B'?

(2)

The coordinates of B' are .

What are the coordinates of C'?

(3)

The coordinates of C' are .

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2

b. hoped i'm right lol

step-by-step explanation: