Fifteen billiard balls are numbered 1 to 15. One billiard ball is selected at random. Determine the odds for and the odds against for (6 Points) a) selecting the number 7 b) selecting a number greater than 10

Odds for & against selecting number 7 = 1/14 & 14

Odds for & against selecting number more than 10 = 4/11 & 11/4

Step-by-step explanation:

Odds for event = Prob (event) / Prob (no event)

Odds against event = Prob (no event) / Prob (event)

Prob (No. 7 chosen) = 1/15 , Prob (No. 7 not chosen) = 14/15

Odds for number 7 = (1/15) ÷ (14/15) = 1/14

Odds against number 7 = (14 / 15) ÷ (1/15) = 14

Prob (No. > 10 chosen) = 4 / 15  , Prob (No. > 10 not chosen) = 11/15

Odds for No. > 10 = (4/15) ÷ (11/15) = 4/11

Odds against No. > 10 = (11/15) ÷  (4/15) = 11/4

yes

step-by-step explanation:

give me the question

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answer is d-29

step-by-step explanation:

since you didn't include the picture, i can give you the description so you know how to pick the correct answer. the third quartile of a data is always shown in a box plot. in the middle of your graph should be a box. the third quartile is the value that goes with the far right edge of the box.