A couple plans to have 3 children. Assuming the probability of having either a boy or a girl is 50%, what is the probability they will have at least 1 girl? Group of answer choices

0.875

0.125

0.375

0.75

0.375

Step-by-step explanation:

The probability of having at least one girl out of 3 children can be calculated as;

P(1 girl, 2 boys) or P(2 girls, 1 boy) or P(3 girls)

Since the P(b) = P(g) = 1/2

Then the probability at any point in time is 1/2 * 1/2 * 1/2 = 1/8

So we have ;

1/8 + 1/8 + 1/8 = 3/8 = 0.375

i believe the correct answer is option 4.principalities were small territories that were run by russian rulers.

which statement correctly defines principalities in northern asia in the 1200s? principalities were small territories that were run by russian rulers.

hope i could ! : )

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1