Bryce made a scale drawing of a shopping center. The scale of the drawing was 1 inch : 4 feet. A bakery in the shopping center is 10 inches in the drawing. How wide is the
actual bakery?

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane

[10 points, algebra 2]according to my answer key the restrictions are -1 and 4. but why not positive 1?

Atemperature of 1.64◦f corresponds to answer in units of ◦c.