A cup slides off a 2.5 m high table with a speed of 2.8 m/s to the right. We can ignore air resistance. What was the cup's horizontal displacement during the fall?

Horizontal distance = 1.98 m (Approx)

Step-by-step explanation:

Given:

Height = 2.5 m

Speed v = 2.8 m/s

Find:

Horizontal displacement

Computation:

s = ut + (1/2)gt²

2.5 = (1/2)(9.8)t²

t² = 0.5102

t = 0.7079 s

Horizontal distance = (v)(t)

Horizontal distance = (2.8)(0.7079)

Horizontal distance = 1.98 m (Approx)