In rectangle ABCD, diagonals AC and BD intersect at E. If AE=3x-28 and DE=.5x+12, find the length of AC.

Given:

In rectangle ABCD, diagonals AC and BD intersect at E, AE=3x-28 and DE=.5x+12.

To find:

The length of AC.

Solution:

We know that, diagonals of a rectangle are equal and they bisect each other.

In rectangle ABCD, diagonals AC and BD intersect at E, so

         ...(i)

Taking , we get

Divide both sides by 2.5.

Now,

Using segment addition property,

        [Using (i)]

Therefore, the length of AC is 40 units.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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step-by-step explanation:

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