A barrel contained 70 gallons of water. Water leaked out of the barrel at a rate of 5 gallons every 3 days. At this rate, how many days did it take for all 70 gallons of water to leak out of the barrel?

42 days

Step-by-step explanation:

Given

Leakage = 5 gallons in 3 days

Required

Determine the number of days it finish leaking out

The scenario can be represented as:

5 gallons = 3 days

and

70 gallons = x

Where x represents the number of days to leak out 70 gallons

Cross Multiply:

Divide both sides by 5

Hence, it'll take 42 days

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15