In ΔJKL, \overline{JL} JL
is extended through point L to point M, \text{m}\angle JKL = (3x-16)^{\circ}m∠JKL=(3x−16)
∘
, \text{m}\angle LJK = (2x+15)^{\circ}m∠LJK=(2x+15)
∘
, and \text{m}\angle KLM = (8x-19)^{\circ}m∠KLM=(8x−19)
∘
. Find \text{m}\angle LJK. m∠LJK.

y=mx+b

step-by-step explanation:

m slope

b y-intercept

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.