100PTS AND BRAINLIEST PLEASE HELP Reflect ΔECD over segment AC. This establishes that _. Then, translate point E' to point A. This establishes that _. Therefore, ΔACB ~ ΔECD by the AA similarity postulate.

a- ∠ABC ≅ ∠E'D'C'; ∠E'D'C' ≅ ∠ABC
b- ∠ACB ≅ ∠E'C'D'; ∠D'E'C' ≅ ∠BAC
c- ∠ACB ≅ ∠E'C'D'; ∠E'D'C' ≅ ∠ABC
d- ∠ABC ≅ ∠E'D'C'; ∠D'E'C' ≅ ∠BAC