What is the vertex for the equation f (x) = 6(x – 10)2 – 4?

Step-by-step explanation:

The vertex form of the equation of quadratic function with vertex (h, k) is:

f(x) = a(x - h)² + q

f(x) = 6(x - 10)² - 4    - given function

so:

a = 6,  h = 10,  q =  -4

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

step-by-step explanation:

i found the koficent of the linear function and i foun c acordind to the strict formula y=kx+c and then i took 2 as an x and replacet it on the formula i found and then foun the y