A professional baseball player hits a homerun on a .75kg baseball. The ball accelerated at a rate of 1200m/s2. How much force did the player hit the ball with?

The force the player hit the ball with is 900 N

Step-by-step explanation:

Given;

mass of the baseball, m = 0.75 kg

acceleration of the ball, a = 1200 m/s²

The force the player hit the ball with is given by the following equations;

F = ma (based on Newton's second law of motion)

where;

F is the applied force

m is mass of the baseball

a is the acceleration of the baseball

F = ma

F = (0.75 x 1200)

F = 900 N

Therefore, the force the player hit the ball with is 900 N

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

3x + 18 = 147°

step-by-step explanation:

3x + 18 = 147°, because the value of the central angle is equal to the value of the arc formed by it.

i hope i you.