A charity is conducting a raffle, and it sells one ticket each to 35 women and 21 men. If 5 winners are randomly selected, what is the probability that they are all men? Round to five decimal places.

The probability that they are all men is 0.00533

Step-by-step explanation:

Here, we want to find the probability that all winners selected are men

Total number of ticket sold is 35 + 21 = 56

What this mean is that out of the 56, we are selecting 5 and out of the 21, we are selecting 5 also

So we use a combination formula;

21 C 5/ 56 C 5

= 20,349/3,819,816

The probability is; 0.00532721995

The probability that they are all men is 0.00533

for the first question it would be the second answer for the second question it would be the third answer and for the third question it would be the first answer

step-by-step explanation:

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10