The height h (in feet) of an object after it is launched given by the function h = -16t^2 + v0t+h0 where v0 is the initial vertical vole city, h0 is the initial height of the object, and t is the time (in seconds) after the object is launched . A toy rocket is launched from the ground level with an initial vertical velocity of 96 ft/s. After how many se done will the rocket hit the ground ?

the height h (in feet) of an object after it is launched given by the function h = -16t^2 + v0t+h0 where v0 is the initial vertical vole city, h0 is the initial height of the object, and t is the time (in seconds) after the object is launched .

Step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

14

step-by-step explanation:

14 x 3 = 42