Isaiah and his children went into a grocery store and where they sell apples for $0.50 each and peaches for $1.50 each. Isaiah has $15 to spend and must buy no less than 14 apples and peaches altogether. If Isaiah decided to buy 8 apples, determine the maximum number of peaches that he could buy. If there are no possible solutions, submit an empty answer.

Maximum of 6 peaches, and 8 apples

Explanation:

Given that the quantity of apples and peaches must total to 14, a total cost of $15, with a cost of $0.50 each for apples and a cost of $1.50 each for peaches, we can create a system of equations to solve for each variable.

0.5a + 1.50p = 15.

a + p = 14.

There are many methods that can be used but the easiest one that works for this problem is elimination.

Start by multiplying the top equation by 2 to get rid of the decimals.

0.5 a × 2 + 1.5 p × 2 = 15 × 2.

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18