PLEASE HELP
solve 2v^2+4v=6 by factoring.

v = 1 or -3

Step-by-step explanation:

2v^2 + 4v = 6

take 2 as common

2(v^2 + 2v = 3)

v^2 + 2v = 3

Now,

v^2 + 2v - 3 = 0

v^2 - v + 3v - 3 = 0

v(v - 1) + 3(v - 1) = 0

(v - 1) (v + 3) = 0

v = 1 or -3

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

6 on both sides and twelve on the top and the bottom

step-by-step explanation: