![y=-x^2-12x-4\\\\y=-(x^2+12x)-4\\\\y=-(\underline{x^2+2\cdot x\cdot6+6^2}-6^2)-4\\\\y=-\left[(x+6)^2-36\right]-4\\\\y=-(x+6)^2+36-4\\\\\bold{\underline{y=-(x+6)^2+32}}](/tpl/images/0903/5279/560f5.png)
What is the vertex form of the equation
Y=-x^2-12x-4
Please show all the steps...
Mathematics, 17.11.2020 03:30 yarrito20011307
What is the vertex form of the equation
Y=-x^2-12x-4
Please show all the steps
Answers: 2
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