Given r, s, and p, which angle is not congruent to 4?

Line R, S, and P are parallel lines meaning any lines that pass through them will form the same angles. Look at 4 and 2. One line is intersecting S and P to for the same angles. Corresponding angles in parallel lines which are formed by an intersecting line are equal. Therefore 4 and 2 are equal. That leaves B, C, and D left. 4 is also congruent to 5.  This is because if 4 is congruent to 2 and 2 is congruent to 5 by vertical angles theorem, 5 must be equal to 4 (transitive property of equality: is a=b and b=c then a=c)

That leaves B and D left. Notice the angle made at the very top left. Across from that unlabeled angle is 6. By vertical angles theorem those 2 angles are congruent. The unmarked angle is equal to 2 and 4 because corresponding angles in parallels are congruent. Therefore lets mark that unmarked angle as 0. If the m< 6 = m< 0 and the m<0= the m<4 then m<6 must equal the m<4.

That leaves Just B remaining thus B is NOT congruent to 4

<3 is the answer

Step-by-step explanation:

answer: a) (0,0), (1,1), (2,8), and (3,27).

step-by-step explanation:

0^3=0

1^3=1

2^3=8

3^3=27

in effect, the exponential equation for this would me y=3^x. each x-coordinate cubed is giving the y coordinate, so a is your answer : )