A waterfall has a height of 1700 feet. A pebble is thrown upward from the top of the falls with an initial velocity of  feet per second. The height of the pebble h in feet after t seconds is given by the equation h=-16t^2+24t+1700 . How long after the pebble is thrown will it hit the ground? PLEASE HEL

Step-by-step explanation:

The expression is given as:

Required

Determine how long it will hit the ground

When the pebble is on the ground, this implies that h = 0

So, we have that:

becomes

Reorder

Multiply through by -1

Solve using quadratic formula :

Where

So, we have:

or

or

or

But time can't be negative.

So:

Hence, it will take 11.085 seconds to hit the ground

2.   2 3/5.

3.   2 1/2.

step-by-step explanation:

6 - 3 2/5

= 6 -   17/5

= 30/5 - 17/5

= 13/5

= 2 3/5 (answer).

5 1/4 - 2 3/4

= 21/4 - 11/4

= 10/4

= 2 1/2 (answer).

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !