the perimeter of a rectangular parking lot is 306 M if the length of the parking lot is 82 M what is its width

71 M

Step-by-step explanation:

to find the perimeter you need to add up all the sides (length and width)

in this case they already gave you the perimeter: 306

and the length: 82

there are two sides that are the length so you need to do 82x2 which is 164

now you need to subtract 306-164=142

142 is the sum of the two width but its asking for only one side so 142 divided by 2 is 71

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3