The length of a rectangular deck is 4 times its width. If the deck's perimeter is 30 feet what is the deck's area???

The answer fam is 36 feet^2

Let width be x

Then, length be 4x

Perimeter=2(l+b)

30=2(4x+x)

30=2×5x

30=10x

x=3feet

Length=4×3=12 feet

Width=3 feet

Area=lb

=12×3=36 feet^2

answer: check all that apply, where the options?

step-by-step explanation:

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240