This hydraulic system should produce an output force of 50,000 newtons. How large an area should the output piston have?

Complete question is;

In a hydraulic system, a 100-newton force is applied to a small piston with an area of 0.0020 m².

This hydraulic system should produce an output force of 50,000 newtons. How large an area should the output piston have?

A2 = 1 m²

Step-by-step explanation:

Using Pascal's Law which is here applied to mechanical advantage of a hydraulic piston, we can find the area of the large piston from;

F1/A1 = F2/A2

We are given;

Force of small piston: F1 = 100 N

Area of small piston; A1 = 0.0020 m²

Force of small piston: F2 = 50000 N

Thus;

Making A2 the subject, we have;

A2 = (F2/F1)A1

A2 = (50000/100) × 0.0020

A2 = 1 m²

tangent

step-by-step explanation:

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!