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Mathematics, 16.11.2020 18:10 pineapplepizaaaaa

Given any triangle ABC labeled as shown, law of sines states: A. sin C/a = sin A/b = sin B/c
B. sin A/b = sin B/c = sin C/a
C. sin A/a = sin B/b = sin C/c
D. sin A/a = sin C/b = sin B/c


Given any triangle ABC labeled as shown, law of sines states:

A. sin C/a = sin A/b = sin B/c
B. s

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Given any triangle ABC labeled as shown, law of sines states: A. sin C/a = sin A/b = sin B/c
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