A random sample of 64 SAT scores of students applying for merit scholarships showed an average of 1400 with a standard deviation of 240. The 95% confidence interval for the population mean SAT score is:

1341.2<x<1458.8

Step-by-step explanation:

Given

sample size n = 64

standard deviation = 240

average mean = 1400

z score at 95% CI = 1.96

Required

confidence interval

Confidence interval = xbar ± (z*s/√n)

CI = 1400 ± (1.96*240/√64)

CI = 1400 ± (1.96*240/8)

CI = 1400 ± (1.96*30)

CI = 1400 ± 58.8

CI = (1400-58.8, 1400+58.8)

CI = (1341.2, 1458.8)

Hence the confidence interval for the population is 1341.2<x<1458.8

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.

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step-by-step explanation:

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