A 12 foot ladder is leaning up against a wall. If the angel made between the ladder and the ground is 80 degrees. How far up can the ladder reach the wall? Round to the nearest tenth of a foot

Step-by-step explanation:

Given

Length of the ladder = 12foot

angle of elevation = 80 degrees

Required

Height of the wall (opposite side)

The set up will form a right angled triangle where

length of the ladder is the hypotenuse

height of the wall is opposite;

Using SOH, CAH, TOA trig identity

According to SOH

sin 80 = opp/hyp

sin80 = opp/12

opp = 12sin80

opp = 11.82 feet

Hence the height of the wall is 11.8feet (to the nearest tenth)

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.